Thursday, October 29, 2009

8086 Assembly Language Program to multiply two 16-bit numbers

data segment
num1 dw 1111h
num2 dw 2222h
prod dw 2 dup (0)
data ends

code segment
assume cs:code,ds:data
start:

mov ax,data
mov ds,ax

mov ax,num1
mul num2
lea si,prod
mov [si],ax
add si,2
mov [si],dx

mov ah,4ch
int 21h

code ends
end start
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7 comments:

  1. UnknownFebruary 17, 2014 at 1:44 AM

    DATA SEGMENT

    MT DW 1234H, 1234H

    MR DW 1111H, 1111H

    PD DW 4 DUP(0)

    DATA ENDS

    CODE SEGMENT

    ASSUME DS:DATA, CS:CODE

    START: MOV AX,DATA

    MOV DS,AX

    CLC

    MOV DX,0000H

    MOV BX,0002H

    MOV CL,02H

    MOV SI,0002H

    RPT: MOV AX,MT[SI]

    MUL MR[BX]

    ADD PD[SI+4],AX

    ADC PD[SI+2],DX

    CLC

    DEC SI

    DEC SI

    DEC CL

    JNZ RPT

    CLC

    DEC BX

    DEC BX

    MOV CL,02H

    MOV SI,0002H

    CONT: MOV AX,MT[SI]

    MUL MR[BX]

    ADD PD[SI+2],AX

    ADC PD[SI],DX

    CLC

    DEC SI

    DEC SI

    DEC CL

    JNZ CONT

    INT 3H

    CODE ENDS

    END START


    correct it.........its challenge

    hint hexa multiplication.....

    ReplyDelete
  2. Aliz FoodsApril 12, 2018 at 1:00 AM

    halaaaaaaaaaaaa

    ReplyDelete
  3. Aliz FoodsApril 12, 2018 at 1:00 AM

    wjah ki ya ??
    if u dont make correct code then why are u doing this type of idiot things???

    ReplyDelete
  4. Aliz FoodsApril 12, 2018 at 1:01 AM

    bastard

    ReplyDelete
  5. Aliz FoodsApril 12, 2018 at 1:01 AM

    chwl admi

    ReplyDelete
  6. Aliz FoodsApril 12, 2018 at 1:02 AM

    coder mango lainay gaye hain aap kay
    sahe code nahe ata
    behn nu L....

    ReplyDelete
  7. Aliz FoodsApril 12, 2018 at 1:02 AM

    l means light :)

    ReplyDelete

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